1. It is given that Q(5,k) is the vertex of the graph of the function
y=-x^2+10x-17.
Find the maximum value of the function
2. It is given that P(h,6) us the vertex if the graph of the function y=x^2-6x+15
(a). Find the value of h.
(b). Find the axis of symmetry of the graph
Find the maximum value of the function
2. It is given that P(h,6) us the vertex if the graph of the function y=x^2-6x+15
(a). Find the value of h.
(b). Find the axis of symmetry of the graph
原連結
1. y= -x^2+10x-17= -(x-5)^2+8,
vertex(5,8)=Q(5,k), k=8
2.y=x^2-6x+15=(x-3)^2+6,
(a)vertex(3,6)=P(h,6), h=3
(b)the axis of symmetry of the graph: x-3=0
ps. symmetry<> symmery
1. y= -x^2+10x-17= -(x-5)^2+8,
vertex(5,8)=Q(5,k), k=8
2.y=x^2-6x+15=(x-3)^2+6,
(a)vertex(3,6)=P(h,6), h=3
(b)the axis of symmetry of the graph: x-3=0
ps. symmetry<> symmery
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