In ΔABC, AB=AC=13 and BC=10. P is a point on BC with BP<PC, and H,K are
the orthocentres of ΔAPB and ΔAPC respectively. If HK=2, find PC.
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Show your steps with suitable diagram(s)
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- Dec 08 Tue 2009 21:32
三角形垂心證明(HK)
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